deWorkflowDefinition..::..compareSnapshots Method
compares the two snapshots and return the differences between the two
Namespace:
FlowWright.cDevDeAPI
Assembly:
cDevDeAPI (in cDevDeAPI.dll)
Syntax
public void compareSnapshots( string snapshotID1, string snapshotID2, ref Dictionary<string, clsFigure> oStepsAddedTo1, ref Dictionary<string, clsFigure> oStepsIn2NotIn1, ref Dictionary<string, clsFigure> oSameStepsChanged1, ref Dictionary<string, clsFigure> oSameStepsChanged2, bool oSnapShot1IsCurrentDef, bool oSnapShot2IsCurrentDef )
Public Sub compareSnapshots ( _ snapshotID1 As String, _ snapshotID2 As String, _ ByRef oStepsAddedTo1 As Dictionary(Of String, clsFigure), _ ByRef oStepsIn2NotIn1 As Dictionary(Of String, clsFigure), _ ByRef oSameStepsChanged1 As Dictionary(Of String, clsFigure), _ ByRef oSameStepsChanged2 As Dictionary(Of String, clsFigure), _ oSnapShot1IsCurrentDef As Boolean, _ oSnapShot2IsCurrentDef As Boolean _ )
public: void compareSnapshots( String^ snapshotID1, String^ snapshotID2, Dictionary<String^, clsFigure^>^% oStepsAddedTo1, Dictionary<String^, clsFigure^>^% oStepsIn2NotIn1, Dictionary<String^, clsFigure^>^% oSameStepsChanged1, Dictionary<String^, clsFigure^>^% oSameStepsChanged2, bool^ oSnapShot1IsCurrentDef, bool^ oSnapShot2IsCurrentDef )
Parameters
- snapshotID1
- Type: String
ID of snapshot 1
- snapshotID2
- Type: String
ID of snapshot 2
- oStepsAddedTo1
- Type: Dictionary<(Of <(<'String, clsFigure>)>)>%
Figures that exist on snapshot1 but not on snapshot2
- oStepsIn2NotIn1
- Type: Dictionary<(Of <(<'String, clsFigure>)>)>%
Figures that exist on snapshot2 but not on snapshot1
- oSameStepsChanged1
- Type: Dictionary<(Of <(<'String, clsFigure>)>)>%
Figures that are same, but properties differ
- oSameStepsChanged2
- Type: Dictionary<(Of <(<'String, clsFigure>)>)>%
Figures that are same, but properties differ
- oSnapShot1IsCurrentDef
- Type: Boolean
if set to true [o snap shot1 is current definition].
- oSnapShot2IsCurrentDef
- Type: Boolean
if set to true [o snap shot2 is current definition].